(8x^2+2x+6)+(5x^2-3x+2)=0

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Solution for (8x^2+2x+6)+(5x^2-3x+2)=0 equation: 



(8x^2+2x+6)+(5x^2-3x+2)=0

We get rid of parentheses

8x^2+5x^2+2x-3x+6+2=0

We add all the numbers together, and all the variables

13x^2-1x+8=0

a = 13; b = -1; c = +8;
Δ = b2-4ac
Δ = -12-4·13·8
Δ = -415
Delta is less than zero, so there is no solution for the equation

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